Important Formulas - Geometric Shapes and Solids

ssc preparation, important competetion questions, current affairs of india, latest question asked in competetion papers,


Important Formulas - Geometric Shapes and Solids
Geometric Shape
Description
Formulas
Rectangle
l= Length
b= Breadth
d= Length of diagonal
Area =lb
Perimeter =2(l+b)
d=l2+b2
Square
a= Length of a side
d= Length of diagonal
Area = a2=12d2
Perimeter =4a
d = 2a
Parallelogram
b and c are sides
b= base
h= height
Area =bh
Perimeter =2(b+c)
Rhombus
a= length of each side
b= base
h= height
d1, d2 are the diagonals
Area =bh
(Formula 1 for area)
Area =12d1d2
(Formula 2 for area)
Perimeter =4a
Triangle
a,b and c are sides
b= base
h= height
Area = 12bh
(Formula 1 for area)

Area =s(sa)(sb)(sc)
where s is the semiperimeter
=a+b+c2
(Formula 2 for area - Heron's formula)

Perimeter =a+b+c

Radius of incircle of a triangle
of area A =As
where s is the semiperimeter
=a+b+c2
Equilateral Triangle
a= side
Area =34a2
Perimeter =3a
Radius of incircle of an equilateral triangle of side a =a23
Radius of circumcircle of an equilateral triangle of side a =a3
Trapezium (Trapezoid)
Base a is parallel to base b
h= height
Area =12(a+b)h
Circle
r= radius
d= diameter
d=2r
Area = πr2=14πd2
Circumference =2πr=πd
Circumferenced=π
Sector of Circle
r= radius
θ = central angle
Area, A =
{θ360πr2(if angle is in degrees)12r2θ(if angle is in radians)

Arc Length, s=
{θ180πr(if angle is in degrees)rθ(if angle is in radians)

In the radian system for angular measurement,
2π radians =360°
⇒ 1 radian =180°π
⇒ 1°=π180 radians

Hence,
Angle in Degrees
= Angle in Radians × 180°π

Angle in Radians
= Angle in Degrees × π180°
Ellipse
Major axis length =2a
Minor axis length =2b
Area =πab
Perimeter 2πa2+b22
Rectangular Solid
l= length
w= width
h= height
Total Surface Area
=2lw+2wh+2hl=2(lw+wh+hl)
Volume =lwh
Cube
s= edge
Total Surface Area =6s2
Volume =s3
Right Circular Cylinder
h= height
r= radius of base
Lateral Surface Area
=(2πr)h
Total Surface Area
=(2πr)h+2(πr2)
Volume =(πr2)h
Pyramid
h = height
B = area of the base
Total Surface Area =B + Sum of the areas of the triangular sides
Volume =13Bh
Right Circular Cone
h= height
r= radius of base
Lateral Surface Area
=πrr2+h2=πrs

where s is the slant height
=r2+h2
Total Surface Area
=πrr2+h2+πr2=πrs+πr2
Sphere
r= radius
d = diameter
d=2r
Surface Area =4πr2=πd2
Volume 

Comments

Popular From Month

list of pm with time period

List of changed station name

Daily CA One Liners 11 September 2020

Important Laws in the Constitution of India

Bank/Financial Department | Railway | SSC | UPSC | Defence | Andaman & Nicobar | Andhra Pradesh | Arunachal Pradesh | Assam | Bihar | Chandigarh | Chhattisgarh | Dama & Diu | Dadar & Nagar | Delhi | Goa | Gujarat | Haryana | Himachal Pradesh | J & K | Jharkhand | Karnataka | Kerala | Lakshadweep | Maharashtra | Mizoram | Madhya Pradesh | Manipur | Meghalaya | Nagaland | Odisha | Punjab | Puducherry | Rajasthan | Sikkim | Tamil Nadu | Telangana | Tripura | Uttar Pradesh | Uttarakhand| West Bengal | PSUs | Institute Jobs

Daily CA One Liners 6 Sept 2020 From THE HINDU NEWPAPER

IPL RECORDS-Most Runs Over

Important Amendments to Indian Constitution